2. For Ni the 1\" loriration energy (E) is 736.7 ki/mol 2- is 17530 ki/mol (16 p

Question

2. For Ni the 1" loriration energy (E) is 736.7 ki/mol 2- is 17530 ki/mol (16 points) the sutlination enerev tNi(s)-yNialls 429,751/met Electron affinity is +1560k) a. Calculate the energy for Ni (g) Ni"(g) + 2 e. ? Use Hess's Law b. Write the electron configurations for the ground state of N for the ground state of Ni. C. The Ni ground state has unpaired electrons and is: paramagnetic or diamagnetic ? d. Nickel has five naturally occurring isotopes. The isotope with mass 61.9283 makes up 3.6345% of naturally occurring nickel atoms This isotope has neutrons. Calculate the atoms of this nickel isotope in 1.000 millimole of naturally occurring nickel. protons and

Explanation / Answer

(a)

Ni (g) -------------> Ni2+ (g) + 2 e

deltaH = IE1 + IE2 = 736.7 + 1753.0 = 2489.7 kJ

(b)

Ni (Z=28) G.S.E.C. is 1s2 2s2 2p6 3s2 3p6 4s2 3d8

Ni2+ (Z=28) G.S.E.C. is 1s2 2s2 2p6 3s2 3p6 3d8

(c)

Ni ground state has 2 unpaired electrons and it is paramagnetic in nature.

(d)

This isotope has 28 protons and 33 neutrons.

Moles of this isotope = 1.000 * 3.6345 / 100 = 0.036345 mmol = 3.6345 * 10-5 mol

= 3.6345 * 10-5 * 6.022 * 1023 = 2.189 * 1019 atoms

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