Acid/Base Titration Date 1013 17 Setion Partner Grams of NSOH needed to make soo

Question

Acid/Base Titration Date 1013 17 Setion Partner Grams of NSOH needed to make soo ml of 3 M Na(m solution (Show calculation and give correct significant figures) (2 pts ) (Unless otherwise noted, all blanks are worth 2 pts.) Molarity of HCI stock solution Trial 1 Trial 2 Trial 3 Volume of HCI used in titration. 50mL0m30mL pt) OmL 23 mL Initial Buret Reading NaoH Om Final Buret Reading saon 23m 232m 23mL 232mL 3mL Total Volume NaOH added Calculate Molarity (4 pts each) Average Molarity of NaOH Calculations Trial #1 (4 pts.)

Explanation / Answer

Molar mass of NaOH = (1*22.9897 + 1*15.9994 + 1*1.008) g/mol = 39.9971 g/mol.

Moles of NaOH in 500 mL of 0.3 M NaOH solution = (500 mL)*(1 L/1000 mL)*(0.3 M)*(1 mol/L/1 M) = 0.15 mole.

Grams of NaOH taken = (0.15 mole)*(39.9971 g/mol) = 5.999565 g 6.000 g (ans).

You haven’t provided the molarity of the standardized HCl solution used in the titration. The molarity of HCl is required to find out the molarity of NaOH using the standardization law.

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