41 H-9.0 AM.-1so. 1 k blee oa, 2colg) +4Hyoal.mde, 1. Calulate AN Nor this react

Question

41 H-9.0 AM.-1so. 1 k blee oa, 2colg) +4Hyoal.mde, 1. Calulate AN Nor this reaction using Hess's Law (6 points) for NaH(CHal (12 points) reaction for the AND determine -V2 2. Write a t YR.a the enthalpy change, AH", for that reaction 3. Determine AH in kJ/mol for the preparation of copper(il) nitrate. By the following process: (8 points) (12 points) 4 25.0g of coppertl) nitrate is dissolved in 100.0g of water initially at 22.0*C a. Will the temperature of the salt+ water go higher, go lower, or remain the same? mate the temperature change, AT

Explanation / Answer

Thermochemical equation is:

N2 (g) + 4 H2 (g) + 2 C (graphite) -----------> N2H2(CH3)2 (l) , deltaH0f = ? ----->(1)

From the second equation provided at the top,

N2H2(CH3)2 + 2 O2 -------> 2 CO2 (g) + 4 H2O (g) + N2 (g) , deltaH = - 1803.1 kJ

From this equation,

deltaHr = 2deltaH0f(CO2)+4deltaH0f(H2O)+deltaH0f(N2)-deltaH0f(N2H2(CH3)2)-2deltaH0f(O2)

- 1803.1 = 2(- 393.5) + 4(- 241.8) + (0) - deltaH0f(N2H2(CH3)2)-(0)

deltaH0f(N2H2(CH3)2) = + 50.1 kJ/mol

Therefore,

enthalphy change of reaction (1) = + 50.1 kJ

N2 (g) + 4 H2 (g) + 2 C (graphite) -----------> N2H2(CH3)2 (l) , deltaH0f = + 50.1 kJ/mol

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