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xC Chegg Study [GU cms/mod/ibis/view.php?id-4078484 arástrala a esta barra de ma

ID: 697060 • Letter: X

Question

xC Chegg Study [GU cms/mod/ibis/view.php?id-4078484 arástrala a esta barra de marcadores, Importar marcadores ahora.. Jump to... Print Calorator bN Periodic Table tion 2 of 9 General Chemistry 4th Edition Science Books Cryolice, NayAIF(s), an ore used in the production Balance the equation. of aluminum, can be synthesized using aluminum oxide. Tip: If you need to clear your click the button that looks like two red arrows It 15.0 kilograms of Al-Ois), 51.4 kilograms of NaOH(D, and 51.4 kilograms of HF(g) react completely, how many kilograms of cryolite will be produced? kg Na,AIF, Which reactants will be in excess? What is the total mass of the excess reactants left over after the reaction is complete? NaOH HF kg here to search

Explanation / Answer

Balanced equation is,

Al2O3 + 6 NaOH + 12 HF ------ > 2 Na3AlF6 + 9 H2O

Given that,

Moles if Al2O3 = mass / molar mass = 15000 / ( 54 + 48) = 147.0 moles

Moles of NaOH = 51400 / 40 =1285 moles

Moles of HF = 51400 / 20 = 2570 moles

From the balanced equation,

147.o moles Al2O3 needs 6 mol NaOH and 12 mol HF

Then,

147.0 mol Al2O3 needs 882 mol NaOH and 1764 mol of HF.

Hence, Al2O3 is limiting reagent.

NaOH and HF are excess reagents.

Moles if NaOH remained = 1285 - 882 = 403 mol

Mass of NaOH remained = 403 * 40 = 16.12 kg.

Moles of HF remained = 806 mol

Mass of HF remained = 806 * 20 = 16.12 kg.

Therefore total mass of excess reagents remained = 32.24 kg.