1. Describe what happens physically (eg., energy, location, nature of motion, et

Question

1. Describe what happens physically (eg., energy, location, nature of motion, etc.) to the electron in a hydrogen atom if it is excited from the 1s to the 2p orbital (the selection rules permit this transition because of the different symmetry of the states). 2. Given that En ½ Z-n--Eh , or En--½ ze n-2 (4 aoYi, calculate the ionization energy of the hydrogen atom. (Hint: what happens to the electron when the atom is ionized? How is this reflected in the quantum number n?) The experimental result is 13.6 eV. What is the percent error? What is the source of the error? 3. If we model helium by neglecting the electron-electron repulsion, what is the ionization energy? is The experimental results give an ionization energy of 24.5 eV. What is the percent error in th case? Comment on the reasons for the magnitude of the percent error

Explanation / Answer

As multiple questions are asked, Answering the first question (as per Chegg policy)

When a hydrogen atom is excited from 1s to 2p, the electron of its orbital absorbs some light energy is the forms of photons, (or some other form of energy which the hydrogen atom as received in order to get excited)

Now coming to physical parameters of the electron, since its now in 2p, orbital, its energy is higher, because more force is exerted on it, and also more energy means its moving faster now compared to when it was in 1s orbital of hydrogen.

Nature of motion is in terms of velocity, which is higher now compared to earlier and thus its wavelength changes in response to change in velocity. so it no longer moves in the same orbital, rapidly changes its path to adjust to more energy it just got.

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