23. A 1.00 L flask contains 0.10 mol of C, 0.20 mol of CO2, and 0.30 mol of CO a

Question

23. A 1.00 L flask contains 0.10 mol of C, 0.20 mol of CO2, and 0.30 mol of CO at equilibrium. What is the value of the equilibrium constant (Ke) for the reaction below? C(s) + CO2(g) 2CO(g) (B) 2.2 (A) 4.5 (C) 1.5 (D) 0.45 24. Given the equilibria: PbF2(s) Pb2+(aq) +2F(aq) HF(aq) + H2O(l) H3O+(aq) + F(aq) K, K What is the equilibrium constant for the equilibria? PbF2(s) + 2H3O+(aq) K, 2H2O1) + Pb2 (aq)+2HF(aq) C1 (C) Kg K, At a specific temperature, the equilibrium constant for the reaction 25. N2(g) + 2N0(g) 2N20(g) is 36. What is the value of the equilibrium constant for the reaction? N20(g) ½N2(g) + NO(g) (A) 0.056 (B) 0.17 (C) 6.0 26. For the interhalogenic equilibrium: Cla(g) + Br2(g) 2BrCI(g) iven temperature Kp 7.7. Ifa 1.0L vessel initially contains 1.0 atm of BrCl(g), what will the partial pressure of Ch(8) be at equilibrium? (A) 0.10 atm (C) 0.42 atm (B) 0.21 atm (D) 0.58 atm

Explanation / Answer

23)

solid do not appear in Kc expression

Kc = [CO]/[CO2]

= 0.30/0.20

= 1.5

Answer: C

24)

3rd reaction = 1st reaction - 2*2nd reaction

So, Kc3 = Kc1/Kc2^2

Answer: D

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