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29) Determine the oxidizing agent in the following reaction. Ni(s) + 2 Aga04(aq)

ID: 696103 • Letter: 2

Question

29) Determine the oxidizing agent in the following reaction. Ni(s) + 2 Aga04(aq) Ni(a04)2(aq) +2 Ag(s) A) O B) Ni C) Ag D) C E) This is not an oxidation-reduction reaction 30) 80) To what temperature must a balloon, initially at 25-C and 2.001, be heated in order to have a 31) What mass of NO2 is contained in a 13.0 L tank at 4.58 atm and 385 K7 32) Determine the density of COz gas at STP volume of 6.00 L2 E) 894 K A) 655 K B) 75 K C)993 K D) 403 K 31) D) 692g E) 24.4 g A) 8678 B) 18.8g C) 53.1 g 32) 446 g/L B) 1.80g/L 510gl D)16 g 33) What pressure would a gas mixture in a 10.0 L tank exert if it were composed of 48.5 g He and 94.6 C) 58.7 atm A) 2.24 g/L 33) g CO2 at 398 K7 D) 46.6 atm E) 39.6 atm A) 32.6 atm B) 7.02 atm 34) How many molecules of XeFs are formed from 12.9 L of F2 (at 298 K and 2.60 atm) according to the 34) following reaction? Assume that there is excess Xe. Xe(g) + 3 F2(g) XeF6(g) A) 7.29 1023 molecules XeF6 B) 8.25 1023 molecules XeF6 C) 2.75 1023 molecules XeF6 D) 1.37 1023 molecules XeF6 E) 1.21 1023 molecules XeFe 35) A mixture of 10.0 g of Ne and 10.0 g Ar have a total pressure of 1.6 atm. What is the partial 35) pressure of Ne? A) 0.40 atm B0.54 atm C) 1.3 atm 36) Calculate the wavelength (in nm) of the blue light emitted by a mercury lamp with a frequency of C) 206 nm D) 1.1 atm E) 0.80 atnm 36) 6.88 1014 Ha. A) 675 nm B) 436 nm D) 229 nm E) 485 nm

Explanation / Answer

Q29

Reduction = species that GAINS electrons

Oxidation = process in which a specie will LOSS electrons

Reducing agent = The species that favors reduction, i.e. it will oxidize in order to reduce another species

Oxidizing agent = The species that favors oxidation, i.e. it will reduce in order to oxidise another species

therefore,

AgClO4 contains Ag, the species being reduced, so it fores oxidation of Nickel, that is, AgClO4 is oxidizing agent

Q30

Apply:

V1/T1 = V2/T2

2/(25+273) = 6/(T2)

T2 = 6/2*(298) = 894 K = 612 °C

choose E

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