At a certain temperature, the equilibrium constant K for the following reaction

Question

At a certain temperature, the equilibrium constant K for the following reaction is 1.4: H2(g) 12(g)-2 HI(g) Use this information to complete the following table Suppose a 28. L reaction vessel is filled with 1.3 mol of H2 and 1.3 mol of 12. What can you say about the composition of the mixture in the vesselO There will be very little HI. at equilibrium? There will be very little H2 and I2. Neither of the above is true. What is the equilibrium constant for the following reaction? Round your answer to 2 significant dinits K= 2H1(g) H2(g)+12(g) What is the equilibrium constant for the following reaction? Round your answer to 2 significant dinits K= 3H2(g)+ 312(g) 6H1(g)

Explanation / Answer

if it only has H2 and I2, in the equilbrium, there will be more HI, due to reaction in order to counterbalance equilbirium

therefore

since K> 1, then HI > H2, I2

expect little of H2 and I2

b)

find:

Kreverse ---> 1/Koriginal = 1/1.4 = 0.714

c)

this is 3x of the original so

K3x = (Koriginal)^3 = 1.4*^3 = 2.744

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