Lab 6. Stoichiometry: Mole Ratio Study Explain how the stoichiometric point for

Question

Lab 6. Stoichiometry: Mole Ratio Study Explain how the stoichiometric point for the precipitation reaction was determined. Include a graph with appropriately labeled axes in your explanation. 1. ópts) In a similar experiment 6.00 mL of 1.00 M sodium sulfate (Na2SO4MW = 142.04 g/mol) is reacted with 6.00 mL of 1.00 M barium chloride (BaCl2; MW = 208.24 g/mol) to form barium sulfate (BaS04; Mw = 233.38 g/mol). What mass of product would you expect to obtain at the stoichiometric point of this reaction? Show your work 2. (10pts)

Explanation / Answer

Q1

Stoichiometry can relate moles of species present, since moles are conserved, initial and final moles can be related as well.

Q2

mmol of Na2SO4 = MV = 1*6 = 6 mmol

mmol of BaCl2 = MV = 1*6 = 6 mmol

then, ratio is 1:!

mmol of BaSO4 formed = 6

mass = mmol*MW = (6*10^-3)(233.38) = 1.4 g of BaSO4 are expected.

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