in determining the molar mass of a volatile liquid following the Experimen compl

Question

in determining the molar mass of a volatile liquid following the Experimen complete the table for analysis. (See Report Shet) Record ealculated values with Procedure of this experiment. Complete the tabic the correct number of significant figures. Calculation Zone A. Preparing the Sample Part D.1 1. Mass of dry flask, foil, and rubber band (8) B. Vaporize the Sample 98.2 2. Temperature of boiling water CC) 3. Mass of dry flask, foil, rubber band. and vapor (g) C. Determine the volume and Pressure Part D.2 of the Vapor I. Volume of 125 mL flask (.) 2. Atmospheric pressure (torr, atm) D. Calculations I. Moles of vapor, apor Part D.3 Equation 12. Show calculation. Mass of vapor, mapor (8) Show calculation. 2. 3. Molar mass of vapor (g/mol) chow caleulation mal and 43.1 g/mol respectively.

Explanation / Answer

mass of dry flask, foil and rubber band= 74.722 g

mass of dry flask, foil and rubber band = 74.921 g

Hence mass of vapour = 74.921 g - 74.722 g = 0.199 g

Applying the ideal gas equation, PV =nRT = (m/Mr) RT

where, P= atmospheric pressure= 0.989 atm

V= Volume= 0.152 L

m= mass= 0.199 g

R= gas constant= 0.082 atm.lit.mol-1K-1

T= temperature= 98.7 deg centigrade= 98.7+273= 371.7 K

and is Mr molar mass

Substituting all values we get, Mr = (mRT/PV) = (0.199 x 0.082 x 371.7) / ( 0.989 x0.152) =40.3477 g/mol

now moles of vapour n = (m/Mr) = 0.199/40.3477 =0.00493 mol

Final answer:

D.1. nvapour =  0.00493 mol

D.2. Mass of vapour mvapour =  0.199 g

D.3. Molar mass of vapour Mr = (mRT/PV) = 40.3477 g/mol

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