(3) Two sheets of metal, one of which was known to be iron and the other nickel,
ID: 695849 • Letter: #
Question
(3) Two sheets of metal, one of which was known to be iron and the other nickel, were accidentally separated and the identity of each was lost. The sheets were labeled A and B, and both were weighed. Sheet A weighed 9.48 g and sheet B weighed 10.89 g. When A was placed in 50.00 mL of water, the total volume was 51.2 ml. When B was placed in 50.00 mL of water, the volume was 51.1 mL. The density of iron is 7.9 g/mL and that of nickel is 9.9 B/mL. Calculate the density of each metal and identify each sheet of metal. Show calculations (4) Choose the best answer for each of the following: Suppose you determine the density of a 20.00 mL sample of solution to be 1.025 8/mL. would expect the density of a 5.00 mL sample of this same solution to be: a. 0.512 g/mL b. 0.998 g/mL c. 1.025 g/mLExplanation / Answer
mass of A metal = 9.48g
The volume of metal = 51.2-50 = 1.2ml
The density of metal A = mass/volume in ml
= 9.48g/1.2ml = 7.9g/ml >>>>A metal is iron
mass of B metal = 10.89g
The volume of metal = 51.1-50 = 1.1ml
The density of metal B = mass/volume in ml
= 10.89g/1.1ml = 9.9g/ml >>>>>B metal is nickel
4.20ml of the solution density is 1.025g/ml
5ml of the solution density is 1.025*5/20 = 0.23g/ml>>>.answer
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