A 23.8 L cylinder contains oxygen gas at 20.01C 732 torr how many moles of oxyge

Question

A 23.8 L cylinder contains oxygen gas at 20.01C
732 torr how many moles of oxygen are in the cylinder
So 732 torr x 1 atm divided by 760 torr
Gives me 0.963
How do I set this up
0.963 atm x 23.8 L
Over 0.0821
Can you show me step by step please
How is the answer 0.950 Mol 02
Thank you
Sometimes I need to see this broken down

A 23.8 L cylinder contains oxygen gas at 20.01C
732 torr how many moles of oxygen are in the cylinder
So 732 torr x 1 atm divided by 760 torr
Gives me 0.963
How do I set this up
0.963 atm x 23.8 L
Over 0.0821
Can you show me step by step please
How is the answer 0.950 Mol 02
Thank you
Sometimes I need to see this broken down

A 23.8 L cylinder contains oxygen gas at 20.01C
732 torr how many moles of oxygen are in the cylinder
So 732 torr x 1 atm divided by 760 torr
Gives me 0.963
How do I set this up
0.963 atm x 23.8 L
Over 0.0821
Can you show me step by step please
How is the answer 0.950 Mol 02
Thank you
Sometimes I need to see this broken down


732 torr how many moles of oxygen are in the cylinder
So 732 torr x 1 atm divided by 760 torr
Gives me 0.963
How do I set this up
0.963 atm x 23.8 L
Over 0.0821
Can you show me step by step please
How is the answer 0.950 Mol 02
Thank you
Sometimes I need to see this broken down

Explanation / Answer

1)

volume = 23.8 L

pressure = 732 torr = 0.963 atm

temperature = 20.01 oC = 293.16 K

P V = n R T

0.963 x 23.8 = n x 0.0821 x 293.16

n = 0.952

moles of O2 = 0.952 mol

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