NAME Answer all five questions. Please follow the rules for significant figures.
ID: 695410 • Letter: N
Question
NAME Answer all five questions. Please follow the rules for significant figures. Show all calculations. Write answers only in the blanks provided. Conversion factor for SI units not provided i atm = 760 torr, h-6.626 X 1034 J-s, c-3.0 X 10e m/s,-hcR =-2.18 X 10 18 J, Rydberg constant R= 1.0968 X 10, m-1, cch, Eshv , lin-10"m Lab -Calorimetry 1.) Calculate the enthalpy of neutralization in an acid-base reaction occurring inside a coffee cup calorimeter: (3 points) a) Initial concentration of acid b) Initial concentration of base c) Initial temperature of acid d) Initial temperature of base e) Final temperature of the solution f) Final volume of solution g) Density of the solution 2.3M 2.4M 23.56 °C 23.61 °C 38.24 °C 130.0 ml 1.038 g/ml C or K f) Temperature change in the calorimeter g) Calorimeter constant g) Specific heat of the solution g) Mass of the solution 9.00 J/K 3.8 J /g-°C 8 k.J h) Heat capacity of the solution in k kJ i) Enthalpy of neutralization Space for calculation: CONTD. TO NExExplanation / Answer
The acid and the base are in similar temperatures 23.56 and 23.61, lets take an average
(23.56 + 23.61) / 2 = 23.585 C this will be the initial temperature of solution
Final temp is 38.24 C
Temperature change is 38.24 - 23.59 = 14.65 C
For the mass of the solution, here you have the volume of the solution and density of it so apply
mass = density * volume
mass = 1.038 g/ml * 130 ml = 134.94 grams of solution
Heat capacity of solution is just
Q = mass * heat capacity * Temp. change
Q = 134.94 * 3.8 * 14.65 = 7512.1 Joules or 7.512 KJ
Now calculate the heat to warm calorimeter, this is just the multiplication of the calorimeter constant by the temperature change
Q cal = 19 * 14.65 = 278.35 Joules or 0.278 KJ
now we have to add this two values of heat
7.512 + 0.278 = 7.79 KJ
since the solution is releasing heat then this value must be negative -7.79 KJ this is the enthalpy of neutralization
Related Questions
Navigate
Integrity-first tutoring: explanations and feedback only — we do not complete graded work. Learn more.