A student used 27 g of vegetable oil to heat 21.11 g of water from initial tempe
ID: 694345 • Letter: A
Question
A student used 27 g of vegetable oil to heat 21.11 g of water from initial temperature of 25*C to a final of 31*C. Which statement correctly describes the heat flow in calories? Specific heat of water is 1.00 cal/g*C and specific heat of oil is 0.89 cal?g*C. (Ignore heat gained or lost by the surrounding)
a) the water lost 127 calories of heat and oil gained 127 calories of heat.
b) the water gained 127 calories of heat and oil lost 127 calories of heat.
c) the water lost 144 calories of heat and oil gained 144 calories of heat.
d) the water gained 144 calories of heat and oil lost 144 calories of heat.
Explanation / Answer
The relationship between the heat transfer and mass, specific heat and change in temperature is, q = mc(Tf-Ti) where for water, m = 21.11 g, specific heat, c =1.00 cal/g-C and (Tf-Ti) =(31-25)=6 oC, so plugging the data,
q= 21.11*1*6 =126.66 rounded off to 127oC
So the answer is (b).
Based on conservation of energy, the heat gained by water is equal to the heat lost by the oil.
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