uestion 6 of 8 Map Consider this reaction data: If you were going to graphically

Question

uestion 6 of 8 Map Consider this reaction data: If you were going to graphically determine the activation energy this reaction, what points would you plot? A products Number Number T (K) k(s 225 0394 675 0.784 To avoid rounding errors, use at least point 1: 1 three significant Number Number uimiber figures in all values. point 2: Determine the rise, run, and slope of the line formed by these points rise run slope Number Number What is the activation energy of this reaction? Number J/ mol O Previous ) Check Answer 0 NextExit Hint aboutus careersprivacy policy rems of use , contact us help

Explanation / Answer

point 1:

x = 1/T = 1/225 = 0.0044

y = ln(K) = ln(0.394) = -0.9314

point 2:

x = 1/T = 1/675= 0.001481

y = ln(K) = ln(0.784) = -0.24334

now,

rise = dy = -0.24334--0.9314 = 0.68806

run = dx = 0.001481-0.0044 = -0.002919

slope = dy/dx = 0.68806/-0.002919 = -235.71

now,

Ea/R = -slope

Ea = -R*slope = -8.314*-235.71 = 1959.692 J/mol

Related Questions

Navigate

• Browse (All)
• Browse U
• Subjects

---

---

Integrity-first tutoring: explanations and feedback only — we do not complete graded work. Learn more.