Note how the titration curve past the Equivalence point turns over and seems to

Question

Note how the titration curve past the Equivalence point turns over and seems to level off as more NaOH solution is added In this case the titrant is 1.0 M NaOH. Given this information, what is the pH when the curve levels off? In other words, what pH is approached (asymptotically) as an infinite amount of 1.0 M NaOH is added? a. b. Imagine instead that the titrant was 0.1 M NaOH. Given this information, at what pH would the curve levels off? In other words, what pH is approached (asymptotically) as an infinite amount of 0.10 M NaOH is added?

Explanation / Answer

a)

as we add NaOH, then

[OH-] concentration will approach asymptotically the 0.1 M concentration

pOH = -log(1) = 0

then

pH = 14-0 = 14

the pH that could be achieved in inifinity is 14

b)

as we add NaOH, then

[OH-] concentration will approach asymptotically the 0.1 M concentration

pOH = -log(0.1) = 1

then

pH = 14-1 = 13

the pH that could be achieved in inifinity is 13

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