What did you learn in this experiment? . appendix -2) For the following redox re

Question

What did you learn in this experiment? . appendix -2) For the following redox reaction Cl; (g) + 2 Br . (aq, 2 Cl. (aq) + Br2 (g) a.) Write oxidation half reaction and mention its oxidation number b. Write reduction half reaction and mention its oxidation number able F Kc. Explain How an element is oxidized or reduced What is the Oxidizing agent? What is the Reducing agent? e. Potassium permanganate (KMnO) is an oxidizing agent. What change (increase or decrease) in the oxidation number of manganese (Mn) must occur? Explain. If oxygen gas oxidizes magnesium metal, what change (increase or decrease) in oxidation number of Mg metal will occur? Write an appropriate half reaction of magnesium metal.

Explanation / Answer

Oxidation is loss of electron

Reduction is gain of electron

oxidation half reaction can be written in terms of that ,which looses electron

2Br- ----->Br2 + 2e-

-1 0 oxidation no.

reduction half

Cl2 + 2e- ------>2Cl-

0 -1 oxidation no.

c)

as I already explained oxidation occurs when there loss of electron

and reduction is gain of electrons

d)

oxidizing agent is the one which oxidizes others by snatching electron from them , and in course reduces itself by taking electron

e)

redcing agen is the one which reduces others by giving electron to them , and in course oxidizes itself by loosing electron

f)

2(a)

if it is oxidizing agent ,it means that it should take electrons from others and hence it itself get reduced ,which means its oxidation no. decrease

(b)

lets see

2Mg + O2 -----> 2 MgO

0 0 +2 -2

there is increase in oxidation no. of Mg +2

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