O Topic: Lesson 4.3 Discussion: y University of Oklahoma-CHE × If You Were Going
ID: 692683 • Letter: O
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O Topic: Lesson 4.3 Discussion: y University of Oklahoma-CHE × If You Were Going To Graphics Addison -d www.sapinglearning.com/ib.scms/mod/ibis/view.php?id=3871612 D 12/4/2017 11:55 PM 2.8/3 Gradebook Assignment I' Attempts Score 2 100 2100 Print Calculator Periodic Table Question 6 of 8 Available From: Due Date: Points Possible: Grade Category Description: Policies: Solutions After You can check You can view s You have five a There is no per Consider this reaction data: If you were going to graphically determine the activation energy this reaction, what points would you plot? products 100 Number Number T (K) (s 325 0.373 0.765 To avoid rounding errors, use at least three significant figures in all values. point 1:0031 0.986 50 point 2: .0016 0.267 100 Determine the rise, run, and slope of the line formed by these points rise run eTextbook Number 719 -0.0014 513.5714 O Help With Thi What is the activation energy of this reaction? Web Help & V 4269.83 J/mol O Technical Sup Previous #Try Again Next ExitExplanation / Answer
We need to plot lnK on y axis and 1/T on x axis
K = 0.373
ln K = ln (0.373) = -0.98618
T = 325.0
1/T = 0.00308
point 1 is:
x = 0.00308
y = -0.98618
K = 0.765
ln K = ln (0.765) = -0.26788
T = 625.0
1/T = 0.0016
point 2 is:
x = 0.0016
y = -0.26788
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rise = (y1-y2) = -0.98618 - -0.26788 = -0.7183
rise = (X1-X2) = 0.00308 - 0.0016 = 0.00148
slope = rise/run
= -0.7183/0.00148
= -486.34721
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use
slope = - Ea/R
= -486.34721 = -Ea/8.314
Ea = 4043 J/mol
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