Determination of Acetic Acid in Vinegar Data Sheet Molarity of your NaOH solutio

Question

Determination of Acetic Acid in Vinegar Data Sheet Molarity of your NaOH solution from the previous page: Vinegar Unknown Letter or Number Final Volumeburette Trial Vinear reading Volume NaOH Moles NaOH Molarity vinegar Initial delivered HC2HO2 in Trial Vinegar | reading (mL)1 delivered (mL) | (mL) (mL) (mL) Trial#1ls me l 32.ql-lo.an 3Rful Trial#3 | 301 |39M7 32 blo Average Molarity: Standard Deviation: 1. Calculations: Show your work for the calculation of the molarity of HC H:02 in vinegar from one of the trials above. 2. The molarity indicates the number of moles of solute per liter of solution. Based on your average molarity of the acetic acid in vinegar solutions, how many grams of acetic acid are contained in one liter of vinegar solution? Show your work. 3. The percent acetic acid in vinegar is considered as the number of grams of acetic acid per 100 mL of vinegar. Based on your calculations above, what is the % acetic acid in your vinegar sample? 08. Determination of Acetic Acid in Vinegar

Explanation / Answer

Determination of acetic acid in vinegar

1. Trial #1

moles of NaOH used = molarity x volume

                                  = 0.0936 M x 32.61 ml = 3.0523 mmol

moles of acetic acid = 3.0523 mmol

molarity of vinegar solution = moles/volume

                                            = 3.0523 mmol/3 ml = 1.017 M

2. Trial#1

moles of acetic acid in vinegar = 3.0523 mmol

mass acetic acid in vinegar = moles x molar mass

                                            = 3.0523 x 10^-3 mol x 60.05 g/mol

                                            = 0.183 g

3. Trial#1

percent acetic acid = grams/100 ml vinegar

0.183 g acetic acid in 3 ml vinegar

so in 100 ml = 6.1 g acetic acid

percent acetic acid = 6.1 g/100 ml                               

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