There are two parts to this question, explain each part andshow each step with t

Question

There are two parts to this question, explain each part andshow each step with the correct units and i will give full lifesaver points. Thanks for the help in understanding: Question: The pH of a Ba(OH)2 solution is 10.66 at25 oC. What is the hydroxide ion concentration of thissolution? If the solution volume is 250. ml, how many grams ofBa(OH)2 must have been used to make this solution? There are two parts to this question, explain each part andshow each step with the correct units and i will give full lifesaver points. Thanks for the help in understanding: Question: The pH of a Ba(OH)2 solution is 10.66 at25 oC. What is the hydroxide ion concentration of thissolution? If the solution volume is 250. ml, how many grams ofBa(OH)2 must have been used to make this solution?

Explanation / Answer

We know that pOH = 14 -pH
                              = 14 - 10.66
                              = 3.34 pOH = - log [OH-] [OH-] = 10^-pOH            =10^-3.34            =4.57 * 10^-4 M Molar mass of Ba(OH)2 = 137.33 + 2 ( 16 + 1 ) = 171.33 g /mol Volume of the solution V = 250 mL = 0.25 L Molarity M = ( mass / Molar mass ) / Volume of thesolution in L Plug the values we get mass of the Ba(OH)2. pOH = - log [OH-] [OH-] = 10^-pOH            =10^-3.34            =4.57 * 10^-4 M Molar mass of Ba(OH)2 = 137.33 + 2 ( 16 + 1 ) = 171.33 g /mol Volume of the solution V = 250 mL = 0.25 L Molarity M = ( mass / Molar mass ) / Volume of thesolution in L Plug the values we get mass of the Ba(OH)2.

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