KCl has the same structure as NaCl (Face-centered). The lengthof the unit cell i

Question

KCl has the same structure as NaCl (Face-centered). The lengthof the unit cell is 628 pm. The density of KCl is 1.984 g/cm^3, andits formula mass is 74.55 amu. Using this information, calculateAvogadro's number.
Need to see how to do the calculations KCl has the same structure as NaCl (Face-centered). The lengthof the unit cell is 628 pm. The density of KCl is 1.984 g/cm^3, andits formula mass is 74.55 amu. Using this information, calculateAvogadro's number.
Need to see how to do the calculations

Explanation / Answer

Given length of the unit cell , a = 628 * 10^-10 cm So, Volume of the unit cell ,V = a^3 = (628*10^-10 cm )^3                                              = 2.4767*10^-22 cm^3 density ,d= 1.984 g / cm^3 Mass of an atom , m = formula mass / avagadro number                                = 74.55amu / N                                = 74.55 /N                               So mass of the unit cell , M = No . of atoms in the unit cell* mass of each atom                                            =4* m Density of unit cell = M / V                    1.984= [4*  74.55/ N ] / [2.4767 * 10^-22 ]                       N = 60.686 * 10^22                            =6.0686*10^23

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