A new temperature scale is proposed based on the melting andboiling point of ben

Question

A new temperature scale is proposed based on the melting andboiling point of benzene. ( the melting point os benzeneis  5.53 (degree Celsius) and the boiling point ofbenzene is 80.10 (degree Celsius)). Zero (degree) on the new scale is the melting point of benzene and100 (degree) on the new scale is the melting point of benzene. Whatare the freezing and boiling points of water on this newtemperature scale Zero (degree) on the new scale is the melting point of benzene and100 (degree) on the new scale is the melting point of benzene. Whatare the freezing and boiling points of water on this newtemperature scale

Explanation / Answer

The melting point of benzene in the Celsius scale =5.530C The boiling point of benzene in the Celsius cale =80.100C On the new scale (assume X scale) the melting point ofbenzene is 00 The boiling point of benzene = 1000C The relationship between the Celsius scale and the newtemperature scale basing on the melting and boiling points ofbenzene                        (0C - 5.53) / (80.10 - 5.53) = (x - 0) / (100 - 0)                                     1.340C - 7.42 = x The freezing point of water on the Celsius scale =00C The freezing point of water on the new scale (X -scale)                                      1.340C - 7.42 = x                                       1.34* 00C - 7.41 = X                                               X= -7.420X The boiling point of water on the Celsius scale is1000C The boiling point of water on the new scale (X -scale)                                         1.340C - 7.42 = X                                     1.34 * 1000C - 7.42 = X                                                  X=126.580X The boiling point of benzene = 1000C The relationship between the Celsius scale and the newtemperature scale basing on the melting and boiling points ofbenzene                        (0C - 5.53) / (80.10 - 5.53) = (x - 0) / (100 - 0)                                     1.340C - 7.42 = x The freezing point of water on the Celsius scale =00C The freezing point of water on the new scale (X -scale)                                      1.340C - 7.42 = x                                       1.34* 00C - 7.41 = X                                               X= -7.420X The boiling point of water on the Celsius scale is1000C The boiling point of water on the new scale (X -scale)                                         1.340C - 7.42 = X                                     1.34 * 1000C - 7.42 = X                                                  X=126.580X

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