I have been trying very hard to understand how to do thisquestion but I cant fig
ID: 691197 • Letter: I
Question
I have been trying very hard to understand how to do thisquestion but I cant figure it out. Find the pH1.0 liter of 0.1M glycine hydrochloride (pka values are 2.3and 9.7) to which has been added 100ml of 1M NaOH. I understand this is a Henderson Hasslebach equation problembut I don't understand what pka to use and what concentrations areused in the equation. The given solution is 5.2 Find the pH
1.0 liter of 0.1M glycine hydrochloride (pka values are 2.3and 9.7) to which has been added 100ml of 1M NaOH. I understand this is a Henderson Hasslebach equation problembut I don't understand what pka to use and what concentrations areused in the equation. The given solution is 5.2 1.0 liter of 0.1M glycine hydrochloride (pka values are 2.3and 9.7) to which has been added 100ml of 1M NaOH. I understand this is a Henderson Hasslebach equation problembut I don't understand what pka to use and what concentrations areused in the equation. The given solution is 5.2
Explanation / Answer
The glycine hydrochloride is a diprotic acid is in thefollowing form - HOOC-CH2-NH3+ Here the pKa of -COOH is 2.3 and pKa of-NH3+ is 9.7. Greater pKa indicates the loweracidity of the -NH3+ . Hence when we cantitrate with NaOH, the proton comes from -COOH, hence we can usethe pKa value 2.3 in Henderson Hasslebach equation.Related Questions
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