Please Submit Answers Only. No work shown or explanations areneeded. All Answers

Question

Please Submit Answers Only. No work shown or explanations areneeded. All Answers must be in correct number of significantfigures. The answers are NOT A) 128 * 10^2 Kg, C) 297K, D) 65.015KPa so please submit new correct answers only andremember to use correct significant figures.

Many gases are shipped in high-pressure containers. Consider asteel tank whose volume is 65.0 L andwhich contains O2 gas at a pressure of 15100 kPa at 22°C.

(a) What mass of O2 does the tank contain?
kg

(c) At what temperature would the pressure in the tank equal 150atm?
K

(d) What would be the pressure of the gas, in kPa, if it weretransferred to a container at 24°C whose volume is 52.60 L?
kPa

Explanation / Answer

a) moles = P x V / R x T = [ (15100/101.325) atm x 65.0 L ] / [0.0821 L-atm/mol-K x 295 K] = 400 moles 400 moles O2 x 32 g/mol = 12800 g = 12.8 kilograms c) T = P x V / n x R = 150 atm x 65.0 L / 400moles x 0.0821 L-atm/mol-K = 300 K (sorry, but that's theanswer I get, too) d) P = n x R x T/ V = [400 moles x0.0821 L-atm/mol-K x 297 K ] / 52.6 L = 185 atm 185 atm x 101.325 kPa/atm = 18700 kPa see if these answers work!

Related Questions

Navigate

• Browse (All)
• Browse P
• Subjects

---

---

Integrity-first tutoring: explanations and feedback only — we do not complete graded work. Learn more.