TOR5 redox balance KMnO4 + KCl (JB) C19 (Points: 7.14) The following redox equat

Question

TOR5 redox balance KMnO4 + KCl (JB) C19

(Points: 7.14) The following redox equation occurs in acidic aqueous solution.When it is balanced with the smallest whole numbercoefficients, what is the coefficient for chlorine gas?

KMnO4(aq) + KCl(aq) +H2SO4(aq) = MnSO4(aq)+ K2SO4(aq) + Cl2(g)



1. 10

2. 8

3. 1

4. 3

5. 5

TOR5 redox balance KMnO4 + KCl (JB) C19

(Points: 7.14) The following redox equation occurs in acidic aqueous solution.When it is balanced with the smallest whole numbercoefficients, what is the coefficient for chlorine gas?

KMnO4(aq) + KCl(aq) +H2SO4(aq) = MnSO4(aq)+ K2SO4(aq) + Cl2(g)



1. 10

2. 8

3. 1

4. 3

5. 5

Explanation / Answer

2 KMnO4 + 10 KCl + 14 H2SO4 = 2 MnSO4 + 5 Cl2 + 12 KHSO4 + 8H2O Hence the smallest coefficient for chlorine gas is 5. OR, This can be complete redox equation. You can add H2O to balance Hand O at any time. 2(8H+ + MnO4- + 5e- --> Mn2+ + 4H2O) 5(2Cl- --> Cl2(g) + 2e-) And,         16H+ + 2MnO4- + 10Cl---> 2Mn2+ + 5Cl2 +8H2O hence, coefficient of chlorine gas is 5. Hope that help!!!!

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