buffer is prepared by mixing 184 ml of 0.442 hydrochloricacid and 0.500 L of 0.4

Question

buffer is prepared by mixing 184 ml of 0.442 hydrochloricacid and 0.500 L of 0.400 M sodium acetate. (ka=1.8 x 10-5) what is the balanced reaction that describes the buffer thatwas produced. what is the ph of the buffer system ? how many grams of KOH must be added to the 0.500L of thebuffer to change pH by 0.15 units? what is the balanced reaction that describes the buffer thatwas produced. what is the ph of the buffer system ? how many grams of KOH must be added to the 0.500L of thebuffer to change pH by 0.15 units?

Explanation / Answer

The balanced equation of the given reation is -         CH3COO- (aq) + H+ (aq) <-----> CH3COOH we have - Concentration of sodium acetate = 0.400 M *0.5 L / (0.5+ 0.184 L)                                                   = 0.292 M Concentration of HCl added = 0.442 M * 0.184 L / (0.5 +0.184)                                             = 0.118 M Thus -                           CH3COO-(aq) + H+ (aq) <-----> CH3COOH   I(M)              0.292                                                   0     C                    -0.118                                                0.118           F                   0.174                                                     0.118 Thus pH = 4.74 + log (0.174 /0.118)                = 4.90             

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