Part E Give the name of the first oxide. chromium(VI) oxide chromium(III) oxide

Question

Part E Give the name of the first oxide.
chromium(VI) oxide chromium(III) oxide chromium(IV) oxide chromium(V) oxide chromium(II) oxide


chromium(VI) oxide chromium(III) oxide chromium(IV) oxide chromium(V) oxide chromium(II) oxide


chromium(VI) oxide chromium(III) oxide chromium(IV) oxide chromium(V) oxide chromium(II) oxide


chromium(VI) oxide chromium(III) oxide chromium(IV) oxide chromium(V) oxide chromium(II) oxide


chromium(VI) oxide chromium(III) oxide chromium(IV) oxide chromium(V) oxide chromium(II) oxide


chromium(VI) oxide chromium(III) oxide chromium(IV) oxide chromium(V) oxide chromium(II) oxide


chromium(VI) oxide chromium(III) oxide chromium(IV) oxide chromium(V) oxide chromium(II) oxide


chromium(VI) oxide chromium(III) oxide chromium(IV) oxide chromium(V) oxide chromium(II) oxide


chromium(VI) oxide chromium(III) oxide chromium(IV) oxide chromium(V) oxide chromium(II) oxide


chromium(VI) oxide chromium(III) oxide chromium(IV) oxide chromium(V) oxide chromium(II) oxide

Part F Give the name of the second oxide.
chromium(II) oxide chromium(V) oxide chromium(III) oxide chromium(VI) oxide chromium(IV) oxide


chromium(II) oxide chromium(V) oxide chromium(III) oxide chromium(VI) oxide chromium(IV) oxide


chromium(II) oxide chromium(V) oxide chromium(III) oxide chromium(VI) oxide chromium(IV) oxide


chromium(II) oxide chromium(V) oxide chromium(III) oxide chromium(VI) oxide chromium(IV) oxide


chromium(II) oxide chromium(V) oxide chromium(III) oxide chromium(VI) oxide chromium(IV) oxide


chromium(II) oxide chromium(V) oxide chromium(III) oxide chromium(VI) oxide chromium(IV) oxide


chromium(II) oxide chromium(V) oxide chromium(III) oxide chromium(VI) oxide chromium(IV) oxide


chromium(II) oxide chromium(V) oxide chromium(III) oxide chromium(VI) oxide chromium(IV) oxide


chromium(II) oxide chromium(V) oxide chromium(III) oxide chromium(VI) oxide chromium(IV) oxide


chromium(II) oxide chromium(V) oxide chromium(III) oxide chromium(VI) oxide chromium(IV) oxide

Part G Give the name of the third oxide.
chromium(VI) oxide chromium(III) oxide chromium(IV) oxide chromium(V) oxide chromium(II) oxide

Explanation / Answer

chromium atomic weight = 52 g and that of oxygen = 16 g now valency of oxygen is 2 so general formula of compound is =Cr2Ox 1) total weight of compound = 52* 2+ 16 * x now weight of chromium = 104 g so total weight of compound when chromium is present 76.5% = 104*100/ 76.5 g = 135.947 g now 135.947 = 104 + 16*x x ~= 2 so compound is Cr2O2 so answer is :e) chromium(II) oxide 2) total weight of compound = 52* 2+ 16 * x now weight of chromium = 104 g so total weight of compound when chromium is present 68.4% = 104*100/ 68.4 g = 152.0467 g now 152.0467 = 104 + 16*x x ~= 3 so compound is Cr2O3 so answer is :c) chromium(III) oxide 3) total weight of compound = 52* 2+ 16 * x now weight of chromium = 104 g so total weight of compound when chromium is present 61.9% = 104*100/ 61.9 g = 168.0129 g now 168.0129 = 104 + 16*x x ~= 4 so compound is Cr2O4 so answer is :e) chromium(IV) oxide 4) total weight of compound = 52* 2+ 16 * x now weight of chromium = 104 g so total weight of compound when chromium is present 52% = 104*100/ 52 g = 200 g now 200 = 104 + 16*x x ~= 6 so compound is Cr2O6 so answer is :a) chromium(VI) oxide so answer is :e) chromium(II) oxide 2) total weight of compound = 52* 2+ 16 * x now weight of chromium = 104 g so total weight of compound when chromium is present 68.4% = 104*100/ 68.4 g = 152.0467 g now 152.0467 = 104 + 16*x x ~= 3 so compound is Cr2O3 so answer is :c) chromium(III) oxide 3) total weight of compound = 52* 2+ 16 * x now weight of chromium = 104 g so total weight of compound when chromium is present 61.9% = 104*100/ 61.9 g = 168.0129 g now 168.0129 = 104 + 16*x x ~= 4 so compound is Cr2O4 so answer is :e) chromium(IV) oxide 4) total weight of compound = 52* 2+ 16 * x now weight of chromium = 104 g so total weight of compound when chromium is present 52% = 104*100/ 52 g = 200 g now 200 = 104 + 16*x x ~= 6 so compound is Cr2O6 so answer is :a) chromium(VI) oxide now weight of chromium = 104 g so total weight of compound when chromium is present 68.4% = 104*100/ 68.4 g = 152.0467 g now 152.0467 = 104 + 16*x x ~= 3 so compound is Cr2O3 so answer is :c) chromium(III) oxide 3) total weight of compound = 52* 2+ 16 * x now weight of chromium = 104 g so total weight of compound when chromium is present 61.9% = 104*100/ 61.9 g = 168.0129 g now 168.0129 = 104 + 16*x x ~= 4 so compound is Cr2O4 so answer is :e) chromium(IV) oxide 4) total weight of compound = 52* 2+ 16 * x now weight of chromium = 104 g so total weight of compound when chromium is present 52% = 104*100/ 52 g = 200 g now 200 = 104 + 16*x x ~= 6 so compound is Cr2O6 so answer is :a) chromium(VI) oxide so answer is :c) chromium(III) oxide 3) total weight of compound = 52* 2+ 16 * x now weight of chromium = 104 g so total weight of compound when chromium is present 61.9% = 104*100/ 61.9 g = 168.0129 g now 168.0129 = 104 + 16*x x ~= 4 so compound is Cr2O4 so answer is :e) chromium(IV) oxide 4) total weight of compound = 52* 2+ 16 * x now weight of chromium = 104 g so total weight of compound when chromium is present 52% = 104*100/ 52 g = 200 g now 200 = 104 + 16*x x ~= 6 so compound is Cr2O6 so answer is :a) chromium(VI) oxide now weight of chromium = 104 g so total weight of compound when chromium is present 61.9% = 104*100/ 61.9 g = 168.0129 g now 168.0129 = 104 + 16*x x ~= 4 so compound is Cr2O4 so answer is :e) chromium(IV) oxide 4) total weight of compound = 52* 2+ 16 * x now weight of chromium = 104 g so total weight of compound when chromium is present 52% = 104*100/ 52 g = 200 g now 200 = 104 + 16*x x ~= 6 so compound is Cr2O6 so answer is :a) chromium(VI) oxide so answer is :e) chromium(IV) oxide 4) total weight of compound = 52* 2+ 16 * x now weight of chromium = 104 g so total weight of compound when chromium is present 52% = 104*100/ 52 g = 200 g now 200 = 104 + 16*x x ~= 6 so compound is Cr2O6 so answer is :a) chromium(VI) oxide now weight of chromium = 104 g so total weight of compound when chromium is present 52% = 104*100/ 52 g = 200 g now 200 = 104 + 16*x x ~= 6 so compound is Cr2O6 so answer is :a) chromium(VI) oxide so answer is :a) chromium(VI) oxide

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