(1) If you have 0.5 moles of NaCl, how many grams of salt doyou have? (2) If we
ID: 688428 • Letter: #
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(1) If you have 0.5 moles of NaCl, how many grams of salt doyou have? (2) If we have 0.2 moles of H3PO4 and react it with 0.6 molesof NH3; how many grams of (NH4)3 will we end up with? (3) Nicotine has an empirical formula of C5H7N and a molecularmass of 162.23. What is the molecular formula for thissubstance? (1) If you have 0.5 moles of NaCl, how many grams of salt doyou have? (2) If we have 0.2 moles of H3PO4 and react it with 0.6 molesof NH3; how many grams of (NH4)3 will we end up with? (3) Nicotine has an empirical formula of C5H7N and a molecularmass of 162.23. What is the molecular formula for thissubstance?Explanation / Answer
1. to find mass of the salt, all you do is multiply the moles ofNaCl by the molar mass of NaCl: 0.5moles NaCl x 58 grams of NaCl = 29 g of NaCl 2. so for this problem, the least amount of moles is going to beyour limiting reagent. Since you know the limiting reagent, all youdo is multiply the limiting reagent by the molar mass of(NH4)3: 0.2 moles of H3PO4 x 54 grams of (NH4)3 = 10.8 grams of (NH3)4 3. so you know the empirical formula and the molar mass of thatempirical formula, all you do is divide the molecular mass by theempirical formula mass.: C5H7N = 81.1 grams 162.23/81.1 = 2 so the 2 means that you multiply the empirical formula by 2: C10H14N2 Hope this helped. Don't forget to give Karma please.
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