An aluminum plate weighing 100.0 g is heated to 105.0?C and is then laid on top

Question

An aluminum plate weighing 100.0 g is heated
to 105.0?C and is then laid on top of a copper
plate weighing 100.0 g at 0.0?C in an insulat-
ing container. If the container allows no heat
to escape and absorbs no heat itself, what will
the final temperature of the two metal plates
be? Report your answer to the nearest 0.1 de-
gree.
(Simplifying hint: delta T calculations give the
same result whether they are done in Celsius
or Kelvins, so do this problem with the tem-
peratures in degrees Celsius. Even though
the delta T in this problem is broken up into ini-
tial and final temperatures, it is still a T
problem, and can be done without converting
temperatures to Kelvins.)
Answer in units of C.

Explanation / Answer

Let final temperature = Tf Heat absorbed by copper plate = mass * specific heat *temperature difference                                                 =100.0 g * 0.385 J/ (g.C) * (Tf -0) . Heat given out by aluminum plate = 100.0 g * 0.902 J/ (g.C) *(105.0 - Tf) . Heat given out by Aluminum = Heat absorbed by copper 100.0 g * 0.902 J/ (g.C) * (105.0 - Tf) = 100.0 g *0.385 J/ (g.C) * (Tf -0)    94.71 - 0.902 Tf = 0.385 Tf 1.287 Tf = 94.71 Final temperature, Tf = 73.6 C

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