for part a) can anyone provide the procedureto calculate the mole fraction, beca
ID: 688224 • Letter: F
Question
for part a) can anyone provide the procedureto calculate the mole fraction, because I am not sure how todo the derivative for it. thanks 10E(b). what proportions of benzene andethylbenzene should be mixed by mole fraction in order toachieve the greatest entropy of mixing? (no value aregiven in this question) the correct answer is Xa =0.5, Xb=0.5. how to do this question !? what is the procedurefor it!? for part a) can anyone provide the procedureto calculate the mole fraction, because I am not sure how todo the derivative for it. thanks 10E(b). what proportions of benzene andethylbenzene should be mixed by mole fraction in order toachieve the greatest entropy of mixing? (no value aregiven in this question) the correct answer is Xa =0.5, Xb=0.5. how to do this question !? what is the procedurefor it!? 10E(b). what proportions of benzene andethylbenzene should be mixed by mole fraction in order toachieve the greatest entropy of mixing? (no value aregiven in this question) the correct answer is Xa =0.5, Xb=0.5. how to do this question !? what is the procedurefor it!?Explanation / Answer
1 mole NaCl
3.57 g NaCl
x
---------------------
=
0.0611 mole NaCl
58.44 g NaCl
1 mole H2O
25.0 g H2O
x
---------------------
=
1.39 mole H2O
18.02 g H2O
Substitute these two quantities into the defining equation formole fraction.
0.0611 mol NaCl
XNaCl
=
--------------------
=
0.0421
(0.0611 + 1.39) mol solution
1.39 mole H2O
Xwater
=
--------------------
=
0.958
(0.0611 + 1.39) mol solution
Note that within the limits of the significant figuresthat XNaCl + Xwater = 1. The sum of themole fractions for a solution will equal 1. In our exampleabove, after we have calculated one mole fraction we could havesubtracted it from 1 to obtain the other.
moles of componenti Xi = ------------------------ total moles of solutionRelated Questions
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