1) a 50.0 ml sample of a 1.00 M solution of CuSO4 is mixedwith 50.0 ml of 2.00 M
ID: 688067 • Letter: 1
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1) a 50.0 ml sample of a 1.00 M solution of CuSO4 is mixedwith 50.0 ml of 2.00 M KOH in a calorimeter. the temperature ofboth solutions was 20.2 C before mixing and 26.3C after mixing. theheat capacity of the calorimeter is 12.1 J/K. from these datacalculate H for the process. CuSO4(1M) + 2KOH(2M)------- Cu(OH)2(s) + K2SO4(0.5M) assume the specific heat and density of the solution aftermixing are the same as those of pure water 1) a 50.0 ml sample of a 1.00 M solution of CuSO4 is mixedwith 50.0 ml of 2.00 M KOH in a calorimeter. the temperature ofboth solutions was 20.2 C before mixing and 26.3C after mixing. theheat capacity of the calorimeter is 12.1 J/K. from these datacalculate H for the process. CuSO4(1M) + 2KOH(2M)------- Cu(OH)2(s) + K2SO4(0.5M) assume the specific heat and density of the solution aftermixing are the same as those of pure waterExplanation / Answer
100 mL of solution; assume has specific heat capacity of water anddensity of water Q = 12.1 J/K *(26.3 - 20.2)C + (100 mL)*(1 g/ mL)*(4.18J/g/C)*(26.3 - 20.2)C Q= 2623.61 Joules amount of reaction 50 mL *(1 L/1000 mL)*(1 mol CuSO4/1L) =0.05 mol CuSO4 reacted (with a stoichiometric amount of KOH) H = Q/moles = (2623.61 J/ 0.05 mol CuSO4)*(1 kJ/ 1000J) =52.5 kJ/mol CuSO4
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