Using the information below, calculate H for the followingrxn at 25 C: NH 4 NO 3

Question

Using the information below, calculate H for the followingrxn at 25 C:

NH4NO3(s) -->2H2O(g) + N2O(g)


Additional Information:
NH4NO3(s) --> NH4+(aq) + NO3-(aq)             H = +25.3 kJ/mol @ 25 C
H2O(g)                                                             Hf = -242 kJ/mol
N2O(g)                                                            Hf = +82 kJ/mol
NH4+(aq)               Hf = -133 kJ/mol                  
NO3-(aq)                                                                             Hf = -205 kJ/mol

Explanation / Answer

NH4NO3(s) -->NH4+(aq) +NO3-(aq)             H = +25.3 kJ/mol H = H products - Hreactants 25.3 = H NH4+ + H NO3- - ( H NH4NO3 )        = -133 -205-  H NH4NO3 H NH4NO3 = -363.3 KJ / mol 25.3 = H NH4+ + H NO3- - ( H NH4NO3 )        = -133 -205-  H NH4NO3 H NH4NO3 = -363.3 KJ / mol NH4NO3(s) -->2H2O(g) +N2O(g)    : H
H = H products - Hreactants
      = 2 * H H2O +H N2O - ( H NH4NO3 )       = 2 * -242 + 82 - ( -363.3)       = -38.7 KJ / mol

Related Questions

Navigate

• Browse (All)
• Browse U
• Subjects

---

---

Integrity-first tutoring: explanations and feedback only — we do not complete graded work. Learn more.