Problem 7: Calculate the molarity of a Ti 3+ (aq) solution if100.0 mL of this so

Question

Problem 7: Calculate the molarity of a Ti 3+ (aq) solution if100.0
mL of this solution requires 29.8 mL of 32.1 mM MnO4 (aq)for
complete reaction. Use the balanced equation from Problem 3 to
answer this question.

This is the balanced equation:

3Ti 3+ + H2O + MnO4 3TiO 2+ + 2H + + MnO2

This is a three step problem.

1) Calculate moles of MnO4 using
M×V (32.1 mM is 32.1×10 3M)
2) Convert moles of MnO4 to moles of Ti 3+ using the balancedequation.
3) Calculate molarity using moles of Ti 3+ ÷ volume of Ti3+
The calculations are all multiplication and division, so just
count the fewest digits in any of your measurements to
determine how many significant digits to keep in your answer.

Explanation / Answer

From the given information, we have - The number of moles of MnO4- inthe reaction = 32.1*10-3 M * 0.0298 L                                                                        = 9.56*10-4 mole According to balanced equatin we require the3*9.56*10-4 moles of Ti+3 . Hence theconcentration of the Ti+3 is                                                                       = 3*9.56*10-4 moles / 0.1 L                                                                       = 0.0286 M

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