The dipole moment of HCl is found to be 1.0 D,representing a charge separation o

Question

The dipole moment of HCl is found to be 1.0 D,representing a charge separation of about 0.17 of anelectron charge; the excess positive charge at the H nuclerus, theexcess electron charge at the Cl nucleus. (4.8 D represents a unitcharge separated by one Å). The dipole moment in HBr is 0.8D. What fraction of a positive charge is found at the H nucleus inHBr.
I have no idea what the question is asking, can someoneexplain it to me? Thank you!!!
I have no idea what the question is asking, can someoneexplain it to me? Thank you!!!

Explanation / Answer

The dipole moment is given by the equation = fractionof charge x distance of charge separation Also, the charge of an electron is the same in magnitude asthat of a positive charge, so to find the fraction of positivecharge you just need to set up two equations. The first relates thedipole mement of HCL to the given distance and charge fraction tofind the charge. The second uses the same equation (above) to usethe charge to find the fraction from a given distance, charge, anddipole moment. Long explanation, hope it helps!

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