Problem#1: A solution is prepared by dissolving 0.14 mol of aceticacid and 0.14

Question

Problem#1: A solution is prepared by dissolving 0.14 mol of aceticacid and 0.14 mol of ammonium chloride in enough water to make1.0 L of solution. Find the concentration of ammonia in thesolution. Express your answer using twosignificant figures. Problem#1: A solution is prepared by dissolving 0.14 mol of aceticacid and 0.14 mol of ammonium chloride in enough water to make1.0 L of solution. Find the concentration of ammonia in thesolution. Express your answer using twosignificant figures. Find the concentration of ammonia in thesolution. Express your answer using twosignificant figures.

Explanation / Answer

A solution is prepared by dissolving 0.14 mol of aceticacid and 0.14 mol of ammonium chloride in enough water to make1.0 L of solution. the proposed reaction can be as shown: CH3COOH + NH4Cl -> NH3 +H2O + CH3COCl so here 1 mole of CH3COOH reacts withNH4Cl to give one mole of NH3 so 0.14 will give 0.14 moles of NH3 now the concentration of ammonia = no of moles of it / volumeof solution                                                      = 0.14/1                                                       = 0.14 mol/L so 0.14 will give 0.14 moles of NH3 now the concentration of ammonia = no of moles of it / volumeof solution                                                      = 0.14/1                                                       = 0.14 mol/L

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