ANY HELP IS MUCH APPRECIATED, I ALWAYS RATE, THANKS!!! . The forces measured by

Question

ANY HELP IS MUCH APPRECIATED, I ALWAYS RATE, THANKS!!! . The forces measured by AFM (atomic force microscopy) ariseprimarily from interactions between electrons of the stylus and onthe surface. To get an idea of the magnitudes of these forces,calculate the force acting between two electrons separated by 2.0nm. To calculate the force between the electons, use F = - dV/dr , where V is their mutual Coulombic potential energy and r istheir separation. . ANY HELP IS MUCH APPRECIATED, I ALWAYS RATE, THANKS!!! . The forces measured by AFM (atomic force microscopy) ariseprimarily from interactions between electrons of the stylus and onthe surface. To get an idea of the magnitudes of these forces,calculate the force acting between two electrons separated by 2.0nm. To calculate the force between the electons, use F = - dV/dr , where V is their mutual Coulombic potential energy and r istheir separation. .

Explanation / Answer

F = -dV /dr Here, V = kq1q2 / r ; in whichq1 , q2 are cahrges of electron (ofcourse for this case q1 =q2 =q = charge of electron) and k is constant of value 9x10^9 Nm^2 / C^2 F = - d(kq1q2 / r)/dr         =-kq1q2 (-1 r^2)         = kq^2/  r^2                      (Since q1 =q2 =q)         = {(9x10^9 Nm^2 /C^2 )* (1.6x10^-19C)^2 }/ (2.0x10^-9m)^2         = 7.2x10^-1 N         = 0.72N Hence, the force acting between two electrons is 0.72N

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