The emission spectrum below for a one-electron (hydrogen like)species in the gas
ID: 686647 • Letter: T
Question
The emission spectrum below for a one-electron (hydrogen like)species in the gas phase shows all the lines, before they mergetogether, resulting from transitions to the first excited statefrom higher energy states. Line A has a wavelength of 103 nm.(The picture is a spectrum with increasing wavelength from left toright, with line B on the left of Line A. No other information isgiven.)
a) What are the upper and lower principal quantum numberscorresponding to the lines labeled A and B?
b) Identify the one-electron species that exhibits the spectrum.
Explanation / Answer
A = 103 nm n1 =1 n2 = ? RH =1097373.6m-1 1/ = RH [1/n12 -n22 ] 1/(103*10-9 ) = 1097373.6 [1/ 12 -n22 ] n2 =3 but from given data B is lower wave lenththan A in the Spectrum .So B line is corresponds to the nextheigher energy state to A heigher energy level A n1 =1 , n2 = 3 B n1 = 1 , n2 = 4 b) the spectrum should be produced byhydrogen . 1/ = RH [1/n12 -n22 ] 1/(103*10-9 ) = 1097373.6 [1/ 12 -n22 ] n2 =3 but from given data B is lower wave lenththan A in the Spectrum .So B line is corresponds to the nextheigher energy state to A heigher energy level A n1 =1 , n2 = 3 B n1 = 1 , n2 = 4 b) the spectrum should be produced byhydrogen .Related Questions
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