1) in the first trial of part A of the procedure, the ratio ofmoles H20/moles CA

Question

1) in the first trial of part A of the procedure, the ratio ofmoles H20/moles CASO4 is found to be 1.93. in the second trial theratio was found to be 1.98. calculate the relative averagedeviation of the two trials. should the student run anothertrial? 2) write equations for the decompostion of H2CO3 andH2SO3. 1) in the first trial of part A of the procedure, the ratio ofmoles H20/moles CASO4 is found to be 1.93. in the second trial theratio was found to be 1.98. calculate the relative averagedeviation of the two trials. should the student run anothertrial? 2) write equations for the decompostion of H2CO3 andH2SO3.

Explanation / Answer

Average = ( 1.93 + 1.98 ) / 2              = 1.955 the difference of two values from the average is 0.025 &0.025 It is not sufficient , we have to perform another trial. The decomposition reactions of H2CO3& H2SO3are                                    H2CO3 --> H2O +CO2
                          H2SO3 --> H2O +SO2                          H2CO3 --> H2O +CO2
                          H2SO3 --> H2O +SO2

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