the following concentration-time data were collected: Time 0 0.467 1 0.267 2 0.1

Question

the following concentration-time data were collected:

Time 0 0.467 1 0.267 2 0.187 3 0.144 4 0.117 5 0.099 6 0.085 7 0.075

Explanation / Answer

X -> Y + Z k = 1.60 M-1min-1 rate = -d[X]/dt = k*[X]a k*[X]a   must have units of M/min (like on theright side). Since k has units of M-1min-1. a must be 2 => (M-1/min)*(M2)= M/min -d[X]/dt = k[X]2 -d[X]/[X]2 = kdt 1/[X] = kt        evaluated from t = 0, [X] = X0    to t = t and [X] =[X] 1/[X] - 1/[X]0 =   kt [X] = [kt + 1/[X]0]-1 [X] = (1.60 M-1min-1*15 min) + 1/0.467M)-1 = 0.0382536042 = 3.83 x 10-2 M

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