From 10 ml cyclopentanol (d=0.949 g/ml) heated with 85%phosphoric acid was obtai

Question

From 10 ml cyclopentanol (d=0.949 g/ml) heated with 85%phosphoric acid was obtained 8.0 ml of cyclopentene (d=0.77 g/ml).what is the percent yield? Someone gave me this explanation but I don't understand thispart: "From the reaction         86 g ofcyclopentanol gives 68 g of cyclopenten      so 1 g of cyclopentanol gives 0.79 gof cyclopenten ". can someone else explain to me what they mean orexplain the solution better? solution I was given: We know that                          Mass = Volume*Density    Mass of Cyclopentanol = 10mL*0.949g/mL                                         =9.49 g     Mass of Cyclopentene = 8mL*0.77 g/mL                                       = 6.16 g    From the reaction         86 g ofcyclopentanol gives 68 g of cyclopenten      so 1 g of cyclopentanol gives 0.79 gof cyclopenten     therefore as per reaction 9.49 g ofcyclopentanol must give 9.49*0.79 g (7.5g) of cyclopentene    We know that % yield =( Actuval  yield/Theoretical yield )(100)                                      = (6.16/7.5 )*100                                       =86% From 10 ml cyclopentanol (d=0.949 g/ml) heated with 85%phosphoric acid was obtained 8.0 ml of cyclopentene (d=0.77 g/ml).what is the percent yield? Someone gave me this explanation but I don't understand thispart: "From the reaction         86 g ofcyclopentanol gives 68 g of cyclopenten      so 1 g of cyclopentanol gives 0.79 gof cyclopenten ". can someone else explain to me what they mean orexplain the solution better?         86 g ofcyclopentanol gives 68 g of cyclopenten      so 1 g of cyclopentanol gives 0.79 gof cyclopenten ". can someone else explain to me what they mean orexplain the solution better? solution I was given: We know that                          Mass = Volume*Density    Mass of Cyclopentanol = 10mL*0.949g/mL                                         =9.49 g     Mass of Cyclopentene = 8mL*0.77 g/mL                                       = 6.16 g    From the reaction         86 g ofcyclopentanol gives 68 g of cyclopenten      so 1 g of cyclopentanol gives 0.79 gof cyclopenten     therefore as per reaction 9.49 g ofcyclopentanol must give 9.49*0.79 g (7.5g) of cyclopentene    We know that % yield =( Actuval  yield/Theoretical yield )(100)                                      = (6.16/7.5 )*100                                       =86%

Explanation / Answer

To understand the given explanation, we have to know thebalanced equation of the given reaction,           C5H9OH +  H+   ---------> C5H8 Molar mass of cyclo pentanol = 86 g/mol Molar mass of the cyclo pentene = 68 g/mol Thus according to above equation,  86 g ofcyclopentanol gives 68 g of cyclopentene. But we have, volume of the cyclopentanol = 10 mL density of cyclopentanol = 0.949 g/mL We know that                          Mass = Volume*Density    Mass of Cyclopentanol = 10mL*0.949g/mL                                         =9.49 g     Mass of Cyclopentene = 8 mL*0.77 g/mL                                       = 6.16 g Thus the actual yield obtained by using the 9.49 g ofthe cyclopentanol = 9.49 g*68 / 86 g                                                                                                           = 7.50 g But we get, only 6.16 g of the cyclopentene Hence -         Percent yield =(actual yield / theorrtical yield)*100                            = = (6.16/7.5 )*100                                       =86%                          Mass = Volume*Density    Mass of Cyclopentanol = 10mL*0.949g/mL                                         =9.49 g     Mass of Cyclopentene = 8 mL*0.77 g/mL                                       = 6.16 g Thus the actual yield obtained by using the 9.49 g ofthe cyclopentanol = 9.49 g*68 / 86 g                                                                                                           = 7.50 g But we get, only 6.16 g of the cyclopentene Hence -         Percent yield =(actual yield / theorrtical yield)*100                            = = (6.16/7.5 )*100                                       =86%                                       =86%

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