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1) For the reaction 5Br - (aq) + BrO 3(aq) + 6H + (aq) ® 3Br 2(aq) + 3H 2 O it w

ID: 685623 • Letter: 1

Question

1)                 For the reaction

5Br-(aq) + BrO3(aq) + 6H+(aq) ® 3Br2(aq) + 3H2O

     

it was found that at a particular instant bromine was beingformed at the rate of 0.039 mol/L s. At that instant,

at what rate was the water being formed?              

at what rate was the bromine ion being oxidized?   

at what rate was H+ beingconsumed?                                

2)                 Dinitrogen pentaoxide decomposes according to the followingequation:

2N2O5(g) ® 4NO2(g) + O2(g)

a)      write an expression forreaction rate in terms of D[ N2O5]

b)      write an expression forreaction rate in terms of D[NO2]

c)      write an expression forreaction rate in terms of D[O2]

Explanation / Answer

          For thereaction          5Br-(aq) + BrO3(aq) + 6H+(aq) ------> 3Br2(aq) + 3H2O          Rate ofthe reaction is change in concentraton with time period .that meansdecreases the concentration of reactants with time or increases theconcentration of producta with time          Rate ofthe reaction = -1/5d/dt[Br-] =-d/dt[BrO3]=-1/6d/dt[H+]=+1/3ddt[Br2]=+1/3ddt[H2O]           Given+1/3ddt [Br2]= 0.039 mol/L
                         +ddt[Br2 ] =(0.039*3  ) mol/L                                               =0.117mol/L    a)      rate wasthe water being formed +1/3ddt[Br2]=+1/3ddt[H2O]          So theformation of bromine and weter is same =0.117 mol/L   b)     rate was the bromineion being oxidized -1/5d/dt[Br-] =+1/3ddt[Br2]                                                                       d/dt[Br-] =-5/3ddt[Br2]                                                                                          =-5/3(0.117mol/L)                                                                                          =-0.195mol/L    c)rate was H+ being consumed-1/6d/dt[H+]=+1/3ddt [Br2]                                                    d/dt[H+]=-6/3 ddt [Br2]                                                                   =-2(0.117mol/L)                                                                   =-0.234mol/L ___________________________________________________________________________________________   2)           The given reaction is   2N2O5(g) -------> 4NO2(g) + O2(g)       Rate of the reaction ischange in concentraton with time period .that means decreases theconcentration of reactants with time or increases the concentrationof producta with time     write an expression for reaction ratein terms of D[ N2O5]= -1/2 d/dt [N2O5]       an expression for reactionrate in terms of D[NO2]    =+1/4d/dt [NO2]       an expression for reactionrate in terms of D[O2] = +d/dt[O2]    _________________________________________________________________________________                 Here - sign means decrease inconcentration of reactant                +signmeans increase in concentration of product