How do I do the last part? Reaction Stoichiometry and Limiting Reagent Suppose t
ID: 684542 • Letter: H
Question
How do I do the last part? Reaction Stoichiometry and Limiting Reagent Suppose that, in the experiment, you start with 3.16 g of FeCl3.6H2O and 11.81 g of K2C2O4.H20 to prepare the iron-oxalate complex. How many moles of FCC13-6H20 do you start with? 1.17times10-2 Previous Tries How many moles of K2C2O4 H2O do you start with? 6.410times10-2 If Fe3+ reacts with C2O42- in a ratio of 1:5, which of the starting materials is the limiting reagent? If Fe3+ reacts with C2O42- in a ratio of 1:6, which of the starting materials is the limiting reagent? If Fe3+ reacts with C2O42- in a ratio of 1:2, which of the starting materials is the limiting reagent? If Fe3+ reacts with C2O42- in a ratio of 1:1, which of the starting materials is in excess?Explanation / Answer
the ratio tells you how many moles of each type areused. in the first ratio 1 mole of Fe^3+ to every 5molesC2O4^2-^ if you have 1.17*10^-2 moles Fe^3+ then you will need5*1.17*10^-2 moles C2O4 = 5.85*10^-2 moles 1:5 Fe^3+ limiting reagent 1:6 need 1.17 *10^-2 *6 = 7.02*10^-2so C2O4^2- is limiting reagent 1:2 need 1.17*10^-2 *2 = 3.34*10^-2 mole Fe^3+ so it isthe limiting reagent 1:1 there are more moles of C2O4^2- so it is excessRelated Questions
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