Fe2O3 (s) + 3CO9g) --> 2Fe(s) + 3CO2(g) calculate the equilibrium constant for t

Question

Fe2O3 (s) + 3CO9g) --> 2Fe(s) + 3CO2(g) calculate the equilibrium constant for the reaction at 298Kgiven the following data: substance Fe2O3(s) CO(g) Fe(s) CO2(g) Gf (kJ/mol) -742.2       -137.2 0 -394.4 please show steps if possible. thank u so muchlifesaver!!! Fe2O3 (s) + 3CO9g) --> 2Fe(s) + 3CO2(g) calculate the equilibrium constant for the reaction at 298Kgiven the following data: substance Fe2O3(s) CO(g) Fe(s) CO2(g) Gf (kJ/mol) -742.2       -137.2 0 -394.4 please show steps if possible. thank u so muchlifesaver!!! substance Fe2O3(s) CO(g) Fe(s) CO2(g) Gf (kJ/mol) -742.2       -137.2 0 -394.4

Explanation / Answer

We Know that :       The given Reaction is :          Fe2O3 (s) +3COg) --> 2Fe(s) + 3CO2(g)       Grxn. = G products   - G reactants                    = 2 ( 0 ) + 3 ( -394.4 ) ] KJ - [-742.2 + 3 ( -137.2 ) ] KJ                      =   -29.4 KJ              G = -RTlnK           -29.4 KJ = -8.314 x 10-3KJ / mol-K x 298K lnK                  K = 1.42 x 105

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