The rate of thereaction of nitrogen monoxide with oxygen was measured at 25C sta

Question

The rate of thereaction of nitrogen monoxide with oxygen was measured at 25C

starting with variousinitial concentrations of NO and O2.

2 NO(g) +O2(g) --> 2NO2(g)

The data collected issummarized in the following table:

Trial #.....Initialconcentration NO (g).....InitialconcentrationO2(g).....Initial reactionrate, mol/l·s

1.....0.020.....0.010.....0.028

2 .....0.020 .....0.020.....0.057

3 .....0.040 .....0.020.....0.227

a. Use the method ofinitial rates to find the reaction orders with respect to NO andO2.

Hint: for which trialswas the concentration of NO changed while [O2]remained

           NO doubles while O2 remains constant: (0.227) / (0.057) =4.0

            Rate= k[NO]^2 [O2]

           Reaction order for NO: 2

           Reaction order for O2: 1

           Overall reaction order: 2 + 1 = 3

Explanation / Answer

We Know that :      The given Reaction is :           2 NO(g)+ O2(g) --> 2NO2(g)         Divide theeqn. ( 1 ) by eqn. ( 2 ) we get :           Theorder with respect to O2 is 1.          Divide theeqn. ( 2 ) by eqn. ( 3 ) we get :           The order with respect to NO is 2.         TheRate = K [ NO ]2 [ O2]           Theoverall order is 2+ 1 = 3.

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