3 energy levels designated E9A), E(B), and E(C). Thewavelength of the radiation
ID: 683471 • Letter: 3
Question
3 energy levels designated E9A), E(B), and E(C). Thewavelength of the radiation emitted from the transitionE(C)-->E(A) is 500 nm. The wavelength of the radiation emittedfrom transition E(B)-->E(A) is 600 nm. The wavelength of theradiation emitted from the transition E(C)-->E(B) is how manynanometers? 2000 nm, 100 nm, 3000 nm, 300 nm, or 3000 A? 3 energy levels designated E9A), E(B), and E(C). Thewavelength of the radiation emitted from the transitionE(C)-->E(A) is 500 nm. The wavelength of the radiation emittedfrom transition E(B)-->E(A) is 600 nm. The wavelength of theradiation emitted from the transition E(C)-->E(B) is how manynanometers? 2000 nm, 100 nm, 3000 nm, 300 nm, or 3000 A?Explanation / Answer
We Know that : According to Max-Planck Relationship: E 1 / EC - EA = 6.627 x 10-34 J - s x 3.0 x108 m / s / 500 x10-9 m = 3.9 x 10-19 J EB -EA = 6.627 x10-34 J - s x 3.0 x 108 m/ s / 600 x 10-9 m = 3.3 x 10-19 J Substract 2 from 1 we get: EB - EA = 0.6 x10-19 J E = h c / = h x c / E = 6.627 x 10-34 J - s x 3.0 x108 m / s / 0.6 x10-19 J = 0.0000033135m = 3313 x 10-9 m = 3313 nm.Related Questions
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