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ID: 683370 • Letter: T
Question
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Hfus(0°C)(H2O, s) 6008 J/mol CP,m(H2O, l) 75.3 J · K 1 ·mol 1 CP,m(H2O, s) 36.8 J · K 1 ·mol 1Explanation / Answer
According tothe law of conservation of energy the heat lost by the warmsubstance is equal to the heat gained by the cold substance . 100g *CP,m(H2O, s) * ( T -(-15oC) = 200g *CP,m(H2O, l) *(25oC- T) ( 100g /18g/mol) *36.8 J · K 1 ·mol 1 * ( T - (-15oC) = (200g/18g/mol) * 75.3 J · K 1 ·mol 1 * (25-T ) final temperature of the mixture = T = 17.144oC.Related Questions
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