Use the following standard state free energy of formation datato calculate the a

Question

Use the following standard state free energy of formation datato calculate the acid dissociation equalibrium constant (Ka) forformic acid? Compound                           G(kJ/mol) HCO2(aq)                           -372.3 H+(aq)                                 0 HCO2-(aq)                        -351 I could not figure out how these two things are connected, inorder to get the answer? Can someone please explain? Use the following standard state free energy of formation datato calculate the acid dissociation equalibrium constant (Ka) forformic acid? Compound                           G(kJ/mol) HCO2(aq)                           -372.3 H+(aq)                                 0 HCO2-(aq)                        -351 I could not figure out how these two things are connected, inorder to get the answer? Can someone please explain?

Explanation / Answer

We Know that :      HCOOH <-------->   H+ + HCOO-       Greaction = Gproducts - Greactants                          =  [ 0 + (-351) ] KJ - [ - 372.3 ]KJ                           = 21.3 KJ         We Know that:         According to gibb'sReaction :           G = -2.303 x R x T x log K        21.3 x103 = - 2.303 x 8.314 J / mol-K x 298K x log K               K = 1.8492 x 10-4                          =  [ 0 + (-351) ] KJ - [ - 372.3 ]KJ                           = 21.3 KJ         We Know that:         According to gibb'sReaction :           G = -2.303 x R x T x log K        21.3 x103 = - 2.303 x 8.314 J / mol-K x 298K x log K               K = 1.8492 x 10-4

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