3.00 g sample of KClO3 decomposes and the oxygen at 240C and0.982 atm is collect

Question

3.00 g sample of KClO3 decomposes and the oxygen at 240C and0.982 atm is collected. What volume of oxygen gas will becollected, assuming 100% yield. (Formula mass of potassiumchlorate is 122.5 g/mol.) a. 304 mL b. 608 mL c. 911 mL d. 1820mL e. none of these
The answer is C but how? 3.00 g sample of KClO3 decomposes and the oxygen at 240C and0.982 atm is collected. What volume of oxygen gas will becollected, assuming 100% yield. (Formula mass of potassiumchlorate is 122.5 g/mol.) a. 304 mL b. 608 mL c. 911 mL d. 1820mL e. none of these
The answer is C but how?

Explanation / Answer

2KClO3 (s) => 2 KCl(s) +3O2 (g) v = nRT/P = (3/122)*0.0821*513 / 0.982 = 10.54 L Oxygen = 10.54*3/2 = 15.81 L O2collected

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