Place the following compounds in order from the highest to the lowestoxidation n
ID: 682414 • Letter: P
Question
Place the following compounds in order from the highest to the lowestoxidation number for carbon.1 C6H12O6
CO2
CH3OH
CH4
C6H6
> 2 C6H12O6
CO2
CH3OH
CH4
C6H6
> 3 C6H12O6
CO2
CH3OH
CH4
C6H6
> 4 C6H12O6
CO2
CH3OH
CH4
C6H6
> 5 C6H12O6
CO2
CH3OH
CH4
C6H6
Place the following compounds in order from the highest to the lowestoxidation number for carbon.
1 C6H12O6
CO2
CH3OH
CH4
C6H6
1 C6H12O6
CO2
CH3OH
CH4
C6H6
1 2 C6H12O6
CO2
CH3OH
CH4
C6H6
2 C6H12O6
CO2
CH3OH
CH4
C6H6
2 3 C6H12O6
CO2
CH3OH
CH4
C6H6
3 C6H12O6
CO2
CH3OH
CH4
C6H6
3 4 C6H12O6
CO2
CH3OH
CH4
C6H6
4 C6H12O6
CO2
CH3OH
CH4
C6H6
4 5 C6H12O6
CO2
CH3OH
CH4
C6H6
5 C6H12O6
CO2
CH3OH
CH4
C6H6
5
1 C6H12O6
CO2
CH3OH
CH4
C6H6
> 2 C6H12O6
CO2
CH3OH
CH4
C6H6
> 3 C6H12O6
CO2
CH3OH
CH4
C6H6
> 4 C6H12O6
CO2
CH3OH
CH4
C6H6
> 5 C6H12O6
CO2
CH3OH
CH4
C6H6
Explanation / Answer
We Know that : The Oxidation state of Carbon in the givencompounds can be calculated as : C6H12O6 6 ( C ) + 12( +1 ) + 6 ( -2 ) = 0 6 ( C) + 12 - 12 = 0 C = 0 CO2 C + 2 ( - 2 ) = 0 C = +4 CH3OH C + 3 ( +1) -2 +1 = 0 C = - 2 CH4 C + 4 ( +1 ) = 0 C = -4 C6H6 6 x C + 6 ( +1 ) = 0 C = - 1 The arrangement of carbon atoms with respect to theincrease in the Oxidation states can be written as : CO2 > C6H12O6 > C6H6 > CH3OH > CH4 C + 4 ( +1 ) = 0 C = -4 C6H6 6 x C + 6 ( +1 ) = 0 C = - 1 The arrangement of carbon atoms with respect to theincrease in the Oxidation states can be written as : CO2 > C6H12O6 > C6H6 > CH3OH > CH4Related Questions
Hire Me For All Your Tutoring Needs
Integrity-first tutoring: clear explanations, guidance, and feedback.
Drop an Email at
drjack9650@gmail.com
drjack9650@gmail.com
Navigate
Integrity-first tutoring: explanations and feedback only — we do not complete graded work. Learn more.