The decomposition of dimethyl ether(CH 3 ) 2 O at 510 C is a 1st order process w

Question

The decomposition of dimethyl ether(CH3)2O at 510 C is a 1st order process witha rate constant of 6.8 x 10-4 S-1 . (CH3)2O(g)----->CH4(g) + H2(g) + CO(g) If the initial pressure of(CH3)2O is 135 torr what is the partialpressure after 1420 s ? hint: ln[A]t= -kt +ln[A]0 The decomposition of dimethyl ether(CH3)2O at 510 C is a 1st order process witha rate constant of 6.8 x 10-4 S-1 . (CH3)2O(g)----->CH4(g) + H2(g) + CO(g) If the initial pressure of(CH3)2O is 135 torr what is the partialpressure after 1420 s ? hint: ln[A]t= -kt +ln[A]0

Explanation / Answer

We Know that :    The given Reaction is :           (CH3)2O(g) ----->CH4(g) +H2(g) + CO(g)         As the aboveReaction follows First - Order Kinetics we can write the Rate ofthe Reaction as :           K = 2.303 / t log Pintial / Pchange           6.8 x10-4 S-1 = 2.303 / 1420S log 135 torr / Pchange                Pchange = 51.4108torr     [ at time t = 1420 S ]                Pchange = 51.4108torr     [ at time t = 1420 S ]

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